## Dart – Remove Elements from Set based on Condition

To remove elements from a Set that satisfy a given condition, call `removeWhere()` method and pass the condition that should be satisfied by the elements to be removed from the Set. `Set.removeWhere(condition)` removes those elements that satisfy the given condition, and retains those elements that do not satisfy the condition.

### Syntax

The syntax to call `removeWhere()` method on Set `mySet` with `condition` passed as argument is

`mySet.removeWhere(condition)`

where the `condition` is a function that accesses element of the Set via function parameter and returns a boolean value.

### Examples

In the following program, we take a Set `mySet`, with some numbers, and remove odd numbers from the Set.

main.dart

```bool isOdd(x) {
if (x % 2 == 1)
return true;
else
return false;
}

void main() {
Set mySet = {1, 3, 6, 10, 13, 15, 20};
print('Original Set  : \$mySet');
mySet.removeWhere(isOdd);
print('Resulting Set : \$mySet');
}```

Output

```Original Set  : {1, 3, 6, 10, 13, 15, 20}
Resulting Set : {6, 10, 20}```

We can also provide a lambda function as argument in the call to `removeWhere()` method.

main.dart

```void main() {
Set mySet = {1, 3, 6, 10, 13, 15, 20};
print('Original Set  : \$mySet');
mySet.removeWhere((x) => x % 2 == 1);
print('Resulting Set : \$mySet');
}```

Output

```Original Set  : {1, 3, 6, 10, 13, 15, 20}
Filtered Set  : {6, 10, 20}```

### Conclusion

In this Dart Tutorial, we learned how to remove the elements of a Set that satisfy a given condition, with examples.