C# Math.Floor() – Examples
In this tutorial, we will learn about the C# Math.Floor() method, and learn how to use this method to find the floor value for given decimal/double number, with the help of examples.
Floor(Decimal)
Math.Floor(d) returns the largest integral value less than or equal to the specified decimal number d.
Syntax
The syntax of Floor() method is
Floor (Decimal d)
where
| Parameter | Description |
|---|---|
| d | A decimal number. |
Return Value
The method returns a decimal number.
Example 1 – Floor(Decimal)
In this example, we will find the floor value of decimal numbers 1.214, 1.99 and 1.0.
Integral values less than or equal to 1.214 are 1, 0, -1, -2 and so on. Of these the largest value is 1. Therefore, Floor(1.214) is 1.
Integral values less than or equal to 3.994 are 3, 2, 1, 0, -1, -2 and so on. Of these the largest value is 3. Therefore, Floor(3.994) is 3.
Integral values less than or equal to 1.0 are 1, 0, -1, -2 and so on. Of these the largest value is 1. Therefore, Floor(1.0) is 1.
C# Program
using System;
class Example {
static void Main(string[] args) {
Decimal d, result;
d = 1.214M;
result = Math.Floor(d);
Console.WriteLine($"Floor({d}) = {result}");
d = 3.994M;
result = Math.Floor(d);
Console.WriteLine($"Floor({d}) = {result}");
d = 1.0M;
result = Math.Floor(d);
Console.WriteLine($"Floor({d}) = {result}");
}
} Output
Floor(1.214) = 1 Floor(3.994) = 3 Floor(1.0) = 1
Floor(Double)
Math.Floor() returns the largest integral value less than or equal to the specified double-precision floating-point number.
Syntax
The syntax of Floor(Double) method is
Floor (Double d)
where
| Parameter | Description |
|---|---|
| d | A double value. |
Return Value
The method returns value of type double.
Example 2 – Floor(Double)
In this example, we will find the floor value of double values 1.214, 1.99 and 1.0.
Integral values less than or equal to 2.214 are 2, 1, 0, -1, -2 and so on. Of these the largest value is 2. Therefore, Floor(2.214) is 2.
Integral values less than or equal to 5.794 are 5, 4, 3, 2, 1, 0, -1, -2 and so on. Of these the largest value is 5. Therefore, Floor(5.794) is 5.
Integral values less than or equal to 1.0 are 1, 0, -1, -2 and so on. Of these the largest value is 1. Therefore, Floor(1.0) is 1.
C# Program
using System;
class Example {
static void Main(string[] args) {
Double d, result;
d = 2.214;
result = Math.Floor(d);
Console.WriteLine($"Floor({d}) = {result}");
d = 5.794;
result = Math.Floor(d);
Console.WriteLine($"Floor({d}) = {result}");
d = 1.0;
result = Math.Floor(d);
Console.WriteLine($"Floor({d}) = {result}");
}
} Output
Floor(2.214) = 2 Floor(5.794) = 5 Floor(1) = 1
Conclusion
In this C# Tutorial, we have learnt the syntax of C# Math.Floor() method, and also learnt how to use this method with the help of C# example programs.