C++ Leap Year Program

An year is said to be leap year if it divisible by 4 and not divisible by 100, with an exception that it is divisible by 400.

In this tutorial, we will write a program to check if given year is leap year.

Algorithm

Following is the algorithm that we shall use to check if given input year is leap year or not.

  1. Read an integer from user, to year variable.
  2. Check the condition if year is exactly divisible by 4 and 100, or the year is exactly divisible by 400.
  3. If the above condition returns true, given year is leap year else it is not leap year.

C++ Program

import java.util.Scanner;

/**
 * Java Program - Check Leap Year
 */
public class CheckLeapYear {

	public static void main(String[] args) {
		//read year from user
		Scanner scanner = new Scanner(System.in);
		System.out.print("Enter year : ");
		int year = scanner.nextInt();

		//check if year is leap year
		if((year%4 == 0 && year%100 != 0) || (year%400 == 0)) {
			System.out.println(year + " is a leap year.");
		} else {
			System.out.println(year + " is not a leap year.");
		}

		scanner.close();
	}
}

Output

C++ Check Leap Year

Conclusion

In this C++ Tutorial, we learned how to check if given year is leap year or not.